How to pass filename to record via REST API

Wowza Developer Dojo
1

Hi. I’m trying to pass in a filename via the REST API via curl that Wowza should use when it records the stream being requested. I’ve tried “baseFile”: “thefilename.mp4” and “currentFile”: “thefilename.mp4”, but both revert to the name of the stream as it is in Wowza. So, for example, instead of recording the file as thefilename.mp4, it records as cam22.stream.mp4.

Is there a different element that I should pass in to set the filename?

Thank you

2

Please post the code you have so far (or dump it in a text file an attach it, if it’s a lot of code)

3

curl -X POST
-H ‘Accept:application/json; charset=utf-8’
-H ‘Content-Type:application/json; charset=utf-8’
http://wowzaserverIPaddress:8087/v2/servers/defaultServer/vhosts/defaultVHost/applications/icd/instances/definst/streamrecorders/cam22.stream_aac
-d ’
{
“instanceName”: “”,
“fileVersionDelegateName”: “”,
“serverName”: “”,
“recorderName”: “cam22.stream_aac”,
“currentSize”: 0,
“segmentSchedule”: “”,
“startOnKeyFrame”: true,
“outputPath”: “”,
“currentFile”: “cam22_031122.mp4”,
“recordData”: false,
“applicationName”: “”,
“moveFirstVideoFrameToZero”: false,
“recorderErrorString”: “”,
“segmentSize”: 0,
“defaultRecorder”: false,
“splitOnTcDiscontinuity”: false,
“version”: “”,
“baseFile”: “”,
“segmentDuration”: 0,
“recordingStartTime”: “”,
“fileTemplate”: “”,
“backBufferTime”: 0,
“segmentationType”: “”,
“currentDuration”: 0,
“fileFormat”: “”,
“recorderState”: “”,
“option”: “”
}’

Also replaced “currentFile” with “baseFile”, but got the same results.

4

Try to add parameter outputFile or else try to specify the filename in outputPath. You may also use fileTemplate and fill in something like "cam22_${RecordingStartTime}"

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